Problem by keren875: help with java code be sure to.?
Can someone inform me what the issue with this code is?
When i operate it, after the user puts in the electricity, the output is each can not operate and enough energy. It should only print 1 of them… i think there is a dilemma with my if/elseif conditioning…. aid?

System.out.println (“Form the Energy you have on that technique:”)
electrical power = sc.nextInt ()

if (electrical power < 0)
System.out.println ("Invalid Entry")
System.exit(0)

else if (apps == 1)
if (system.equals ("Windows XP"))
if (power < 300)
System.out.println ("Can Not Run")
else if (system.equals("Vista"))
if (power < 800)
System.out.println ("Can Not Run")
else if (system.equals ("Windows 7"))
if (power < 500)
System.out.println ("Can Not Run")
if (apps == 2)
if (system.equals ("Windows XP"))
if (power < 500)
System.out.println ("Can Not Run")
else if (system.equals ("Vista"))
if (power < 1000)
System.out.println ("Can Not Run")
else if (system.equals("Windows 7"))
if (power < 800)
System.out.println ("Can Not Run")

if (apps> two)
if (technique.equals(“Windows XP”))
if (power < (500+(apps*50)))
System.out.println ("Can Not Run")
if (system.equals("Vista"))
if (power < (1000+(apps*50)))
System.out.println ("Can Not Run")
if (system.equals ("Windows 7"))
if (power < (800+(apps*50)))
System.out.println ("Can Not Run")

System.out.println ("Enough Power")

System.exit(0)
}}

Best answer:

Solution by MichaelInScarborough
It is really hard to examine your code:
attempt the adhering to:
Method.out.println (“Sort the Energy you have on that system:”)
energy = sc.nextInt ()

if (energy < 0)
System.out.println ("Invalid Entry")
System.exit(0)

if (apps < 1)
System.out.println ("Invalid Entry")
System.exit(0)

String strPrompt[] = new String[]
"Windows XP",
"Windows 7",
"Vista",
"Can Not Run"

switch(apps)

case 1:
if (system.equals (strPrompt[0]) && (power < 300))
System.out.println(strPrompt[3])

else if (system.equals(strPrompt[1]) && (power < 800))
System.out.println(strPrompt[3])

else if (system.equals(strPrompt[2]) && (power < 500))
System.out.println(strPrompt[3])

else
System.out.println ("Invalid Entry")

break
case 2:
if (system.equals (strPrompt[0]) && (power < 500))
System.out.println(strPrompt[3])

else if (system.equals(strPrompt[1]) && (power < 1000))
System.out.println(strPrompt[3])

else if (system.equals(strPrompt[2]) && (power < 800))
System.out.println(strPrompt[3])

else
System.out.println ("Invalid Entry")

break
default:
if (system.equals (strPrompt[0]) && (power < (500 + apps * 50)))
System.out.println(strPrompt[3])

else if (system.equals (strPrompt[0]) && (power < (1000 + apps * 50)))
System.out.println(strPrompt[3])

else if (system.equals (strPrompt[0]) && (power < (800 + apps * 50)))
System.out.println(strPrompt[3])

else
System.out.println ("Invalid Entry")

break

In this way, you find your error far easier.

You could go one step further and pack those three statements for xp, vista, and windows 7 into a function. Then you just had 3 function calls which would set up the logic of your program. A lot of code and options to do mistakes would be rationalized away.

I hope this was helpful.

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Best remedy:

Solution by duderinow
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